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medium
end_to_end
Learning Rate Scheduler
Implement a cosine annealing learning rate scheduler.
The cosine annealing schedule is: $$\text{lr}(t) = \text{lr}_{min} + \frac{1}{2}(\text{lr}_{max} - \text{lr}_{min})\left(1 + \cos\left(\frac{t}{T}\pi\right)\right)$$
where:
- $t$ is the current step (0-indexed)
- $T$ is the total number of steps
- $\text{lr}_{max}$ is the initial (maximum) learning rate
- $\text{lr}_{min}$ is the minimum learning rate
Compute the learning rate for each step from 0 to T-1.
Input:
-
lr_max: maximum learning rate (float) -
lr_min: minimum learning rate (float) -
T: total number of steps (int)
Output: A 1D tensor of shape (T,) with the learning rate at each step.
Hints
learning-rate
scheduler
cosine-annealing
training
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