We can't find the internet
Attempting to reconnect
Something went wrong!
Attempting to reconnect
← JAX Autodiff step 8 of 25
HVP via grad-of-grad
How a gradient changes
A gradient measures how a scalar loss changes with its inputs. The
Hessian measures how that gradient changes. For d inputs it is a
d by d matrix of second derivatives.
Often we only need its product with a vector, H @ v: the rate at which
the gradient changes along x + epsilon*v. This avoids constructing a
dense Hessian with d*d entries. It does not guarantee total memory use
of O(d), since the differentiated computation can store other arrays.
Make a scalar before differentiating again
jax.grad needs a scalar output. If x is a vector, jax.grad(f)(x)
is also a vector, so calling jax.grad(jax.grad(f))(x) raises an error.
It does not return a Hessian. jax.hessian(f)(x) would construct the
full matrix, but that is unnecessary for a single product.
Instead, take the dot product of the gradient with a fixed v, then
differentiate that scalar:
import jax
import jax.numpy as jnp
A = jnp.array([[2.0, 1.0], [1.0, 3.0]])
x = jnp.array([1.0, 2.0])
v = jnp.array([2.0, -1.0])
def f(x):
return 0.5 * x @ A @ x
grad_f = jax.grad(f)
hvp = jax.grad(lambda z: jnp.vdot(grad_f(z), v))(x)
# hvp = [3.0, -1.0]
Differentiating this dot product gives H.T @ v. For a twice
continuously differentiable real scalar function, the Hessian is
symmetric, so this equals H @ v. Here A is symmetric and the loss
is quadratic: its gradient is A @ x and its Hessian is A.
Thus A @ v = [2*2 - 1, 1*2 - 3] = [3, -1].
For these real vectors, jnp.vdot is the usual dot product. Keep v
fixed during differentiation. Capturing it in the outer scope, as
above, is one way to do that. This construction uses reverse-mode
differentiation through another reverse-mode derivative.
Problem
Implement hvp_grad_of_grad(x, A, v) using the nested-gradient method
for f(x) = 0.5 * x @ A @ x.
All inputs are real floating-point JAX arrays. x and v have shape
(d,), and A has shape (d, d) and is symmetric. Hold A and v
fixed. Return a JAX array with shape (d,), containing H @ v.
For this quadratic the answer is A @ v and does not depend on x.
Use that fact to check your answer while practicing nested gradients.
Numerical tests alone cannot enforce which method you use.
Understand the ideas behind this exercise. The Problem tab contains the exact implementation requirements.
How a gradient changes
A gradient measures how a scalar loss changes with its inputs. The
Hessian measures how that gradient changes. For d inputs it is a
d by d matrix of second derivatives.
Often we only need its product with a vector, H @ v: the rate at which
the gradient changes along x + epsilon*v. This avoids constructing a
dense Hessian with d*d entries. It does not guarantee total memory use
of O(d), since the differentiated computation can store other arrays.
Make a scalar before differentiating again
jax.grad needs a scalar output. If x is a vector, jax.grad(f)(x)
is also a vector, so calling jax.grad(jax.grad(f))(x) raises an error.
It does not return a Hessian. jax.hessian(f)(x) would construct the
full matrix, but that is unnecessary for a single product.
Instead, take the dot product of the gradient with a fixed v, then
differentiate that scalar:
import jax
import jax.numpy as jnp
A = jnp.array([[2.0, 1.0], [1.0, 3.0]])
x = jnp.array([1.0, 2.0])
v = jnp.array([2.0, -1.0])
def f(x):
return 0.5 * x @ A @ x
grad_f = jax.grad(f)
hvp = jax.grad(lambda z: jnp.vdot(grad_f(z), v))(x)
# hvp = [3.0, -1.0]
Differentiating this dot product gives H.T @ v. For a twice
continuously differentiable real scalar function, the Hessian is
symmetric, so this equals H @ v. Here A is symmetric and the loss
is quadratic: its gradient is A @ x and its Hessian is A.
Thus A @ v = [2*2 - 1, 1*2 - 3] = [3, -1].
For these real vectors, jnp.vdot is the usual dot product. Keep v
fixed during differentiation. Capturing it in the outer scope, as
above, is one way to do that. This construction uses reverse-mode
differentiation through another reverse-mode derivative.
Compute derivatives by following the operations
Automatic differentiation computes derivatives by applying the chain rule to a program's operations. It does not estimate them by evaluating nearby inputs, as finite differences do, or rearrange the whole expression using symbolic algebra.
For f(g(x)), the chain rule combines the derivative of g with the derivative
of f at g(x). Repeating this process lets a framework differentiate a long
sequence of operations.
Forward mode follows an input change
For a function with n inputs and m outputs, the Jacobian J is an (m, n)
matrix of derivatives. Entry (i, j) describes how output i changes with input
j.
Forward-mode differentiation computes Jv: the output's rate of change when the
input moves in direction v. For example, if f(x) = sum(x_i^2), then at
x = [1, 2] the gradient is [2, 4]. In direction v = [3, 0], the rate of
change is 2 * 3 + 4 * 0 = 6.
This is a directional derivative. It gives one Jacobian column only when v
selects one input coordinate, such as [1, 0].
Reverse mode works backward from an output
Reverse mode computes J^T u, where u weights the outputs. For a scalar loss,
choosing u = 1 gives the gradient with respect to all inputs. This makes reverse
mode useful for training: a model can have many parameters but just one loss.
Forward mode can be useful when you need sensitivity to only a few input directions. Neither mode needs to construct the full Jacobian for these products. That can save substantial memory. Higher-order differentiation can similarly compute a Hessian-vector product without storing the full matrix of second derivatives.
Changing gradient flow changes what is differentiated
A stop-gradient operation keeps a value in the forward calculation but treats it as constant during differentiation. A custom derivative supplies a derivative rule explicitly. It should match the intended function unless the exercise asks for a surrogate, such as an approximation used during training.
Your code, saved here
Sign in to access your accepted solutions and saved draft history. You can keep reading the lesson without an account.
Sign in to your accountStuck?
JAX reference solution
Sign in to track your attempts toward unlocking the reference solution.